document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=60929>Question 60929</A>: <I><SPAN STYLE=\"word-break: break-all;\"> (w-12)(aw+9), where a is a real number and a does not equal 0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #42109 by </B><A HREF=/tutors/aboutme.mpl?userid=jai_kos><B>jai_kos(139)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jai_kos><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=42109\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (w -12)* (aw+9) = 0\r<BR>\n" );
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document.write( "That is (w - 12) = 0             &#61664;(1)\r<BR>\n" );
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document.write( "Or (aw + 9) = 0                  &#61664;(2)\r<BR>\n" );
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document.write( "&#61672; w = 12                           <BR>\n" );
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document.write( "Now substitute w =12 in equation (2), we get\r<BR>\n" );
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document.write( "a *12 + 9 = 0 \r<BR>\n" );
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document.write( "12 a +  9 = 0\r<BR>\n" );
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document.write( "12 a = -9\r<BR>\n" );
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document.write( "a = -9 /12 = - 3 / 4\r<BR>\n" );
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document.write( "Therefore the value for  a = (-3/4)<BR>\n" );
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