document.write( "Question 677820: In which direction does the hyperbola defined by the equation below open?
\n" );
document.write( " Check all that apply.\r
\n" );
document.write( "\n" );
document.write( "(x-3)^2/4^2-(y+5)^2/2^2=1\r
\n" );
document.write( "\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #421073 by stanbon(75887) ![]() You can put this solution on YOUR website! In which direction does the hyperbola defined by the equation below open? \n" ); document.write( "Check all that apply. \n" ); document.write( "(x-3)^2/4^2-(y+5)^2/2^2=1 \n" ); document.write( "------------ \n" ); document.write( "(x-3)^2/16 - (y+5)^2/4 = 1 \n" ); document.write( "----- \n" ); document.write( "Comment:l \n" ); document.write( "Notice that when y = -5, you can solve for \"x\" \n" ); document.write( "--- \n" ); document.write( "Notice that when x = 3, you cannot solve for \"x\" \n" ); document.write( "----- \n" ); document.write( "Notice that the center of the hyperbola is at (3,-5) \n" ); document.write( "------ \n" ); document.write( "Since the curve cannot cross the line x = 3, it must \n" ); document.write( "open to the right and to the left. \n" ); document.write( "============== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |