document.write( "Question 61170: Please help me solve by substitution thanks rob.\r
\n" ); document.write( "\n" ); document.write( "4X + 2y = 3
\n" ); document.write( "y = -X
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Algebra.Com's Answer #42106 by praseena(37)\"\" \"About 
You can put this solution on YOUR website!
Please help me solve by substitution thanks rob.\r
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\n" ); document.write( "\n" ); document.write( "4X + 2y = 3\r
\n" ); document.write( "\n" ); document.write( "y = -X\r
\n" ); document.write( "\n" ); document.write( "here we have y = -x\r
\n" ); document.write( "\n" ); document.write( "now substitute the value y = -x in the first equation\r
\n" ); document.write( "\n" ); document.write( "==> 4x + 2 (-x) = 3\r
\n" ); document.write( "\n" ); document.write( "==> 4x -2x = 3\r
\n" ); document.write( "\n" ); document.write( "==> 2x = 3\r
\n" ); document.write( "\n" ); document.write( "==> 2x/2 =3/2\r
\n" ); document.write( "\n" ); document.write( "==> x = 3/2\r
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\n" ); document.write( "\n" ); document.write( "now we have the value x = 3/2\r
\n" ); document.write( "\n" ); document.write( "now substitute the value x =3/2 in the second equation, y = -x\r
\n" ); document.write( "\n" ); document.write( "==> y = -3/2\r
\n" ); document.write( "\n" ); document.write( "BYE!!!!!!!!!
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