document.write( "Question 677581: you are choosing between two long distance telephone plans. Plan A has a monthly fee of $15 with a charge of $0.08 per minute for all long-distance calls. Plan B has a monthly fee of $3 with a charge of $0.12 per minute for all long-distance calls. How many minutes of long-distance calls in a month make plan A the better deal? \n" ); document.write( "

Algebra.Com's Answer #421035 by partha_ban(41) $\"\"$ $\"About$

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Let m be the minutes of long-distance calls in a month to make plan A the better deal.
\n" ); document.write( "Therefore, charges for Plan A = $15 + 0.08m
\n" ); document.write( "and charges for Plan B = $3 + 0.12m
\n" ); document.write( "By condition,
\n" ); document.write( "3 + .12m > 15 + .08m
\n" ); document.write( ".12m - .08m > 15 - 3
\n" ); document.write( ".04m > 12
\n" ); document.write( " $\"m+%3E+12%2F.04\"$
\n" ); document.write( " $\"m+%3E+%2812+%2A+100%29%2F4\"$
\n" ); document.write( "m > 300
\n" ); document.write( "Therefore more than 300 minutes of long-distance call will make Plan A better deal. \n" ); document.write( "

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