document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=677739>Question 677739</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the point(s) that is a distance 7 from the point (2,5) and is on the line -x+y=3? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #421034 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=421034\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -x+y=3\r<BR>\n" );
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document.write( "y=x+3\r<BR>\n" );
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document.write( "d = sqrt((x2-x1)^2 + (y2-y1)^2)\r<BR>\n" );
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document.write( "d = sqrt((x-2)^2 + (y-5)^2)\r<BR>\n" );
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document.write( "d = sqrt((x-2)^2 + (x+3-5)^2)\r<BR>\n" );
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document.write( "d = sqrt((x-2)^2 + (x-2)^2)\r<BR>\n" );
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document.write( "d = sqrt(2(x-2)^2)\r<BR>\n" );
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document.write( "7 = sqrt(2(x-2)^2)\r<BR>\n" );
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document.write( "7^2 = 2(x-2)^2\r<BR>\n" );
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document.write( "49 = 2(x-2)^2\r<BR>\n" );
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document.write( "2(x-2)^2 = 49\r<BR>\n" );
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document.write( "(x-2)^2 = 49/2\r<BR>\n" );
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document.write( "x - 2 = sqrt(49/2)  or  x - 2 = -sqrt(49/2)\r<BR>\n" );
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document.write( "x - 2 = 7*sqrt(2)/2  or  x - 2 = -7*sqrt(2)/2\r<BR>\n" );
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document.write( "x = 2 + 7*sqrt(2)/2  or  x = 2 - 7*sqrt(2)/2\r<BR>\n" );
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document.write( "x = 6.949747  or  x = -2.949747\r<BR>\n" );
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document.write( "y = x+3\r<BR>\n" );
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document.write( "y = 6.949747+3\r<BR>\n" );
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document.write( "y = 9.949747\r<BR>\n" );
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document.write( "So when x = 6.949747, y is y = 9.949747. Therefore, the point (6.949747, 9.949747) is about 7 units away from (2,5) and this point lies on -x+y = 3\r<BR>\n" );
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document.write( "y = x+3\r<BR>\n" );
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document.write( "y = -2.949747+3\r<BR>\n" );
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document.write( "y = 0.050253\r<BR>\n" );
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document.write( "So when x = -2.949747, y is y = 0.050253. Therefore, the point (-2.949747, 0.050253) is also about 7 units away from (2,5) and this point lies on -x+y = 3<BR>\n" );
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