document.write( "Question 25920: Here is the question. I know that there is a way to set these up, and the instructor said I would start to see a pattern, but she does not explain clearly how to do these. I am confused.\r
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document.write( "60 fluid ounces of a 15% muriatic acid solution is needed to kill algae in a pool. If the technician has a 5% solution and a pure solution on hand, how many ounces of each must be combined to create the 15% solution?\r
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document.write( "I tried to set it up like this:\r
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document.write( ".05X+.10(.15-X)=24(.15)\r
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document.write( "I am getting my numbers put in the wrong place. Please help me.
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document.write( "Thank you. Donna \n" );
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Algebra.Com's Answer #42103 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! Let x=number of ounces of the pure muriatic acid to be combined \n" ); document.write( "Then 60-x=number of ounces of the 5% muriatic acid solution to be combined\r \n" ); document.write( "\n" ); document.write( "Now we know that the amt of pure muriatic acid to be combined (x)(1) plus the amt of pure muriatic acid in the 5% solution (60-x)(.05) has to equal the amt of pure muriatic acid in the final mixture (60)(.15). \n" ); document.write( "Thus, our equation to solve is: \n" ); document.write( "(x)(1)+(60-x)(.05)=(60)(.15) simplifying, we get: \n" ); document.write( "x+3-.05x=9 or \n" ); document.write( ".95x=6 \n" ); document.write( " x=6.31 ounces of pure muriatic acid, and \n" ); document.write( "60-x=60-6.31=53.69 ounces of 5% solution\r \n" ); document.write( "\n" ); document.write( "Lets solve this problem again, focusing on the \"otherstuff\" in the muriatic acid solution\r \n" ); document.write( "\n" ); document.write( "We will still let x=number of ounces of the pure muriatic acid to be combined \n" ); document.write( "Then 60-x=number of ounces of the 5% muriatic acid solution to be combined\r \n" ); document.write( "\n" ); document.write( "Now we know that the amt of \"otherstuff\" in the pure muriatic acid to be combined (x)(0) plus the amt of \"otherstuff\" in the 5% solution (60-x)(.95) has to equal the amt of \"otherstuff\" in the final mixture (60)(.85). \n" ); document.write( "Thus, our equation to solve is:\r \n" ); document.write( "\n" ); document.write( "(60-x)(.95)=(60)(.85) simplifying, we get: \n" ); document.write( "57-.95x=51 or \n" ); document.write( "-.95x=-6 \n" ); document.write( "x=6.31 ounces of pure muriatic acid, and \n" ); document.write( "60-x=60-6.31=53.69 ounces of 5% solution\r \n" ); document.write( "\n" ); document.write( "Hope this helps ------- ptaylor \n" ); document.write( " |