document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1384>Question 1384</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1/x-4 + 5 = 3/x-4.  I need to know how to solve this type of equation. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #421 by </B><A HREF=/tutors/aboutme.mpl?userid=usyim88hk><B>usyim88hk(158)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=usyim88hk><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=421\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First we should multiply both sides by (x-4) so that we won't have any fraction on both sides of the equation:<BR>\n" );
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document.write( "(x-4)(1/x-4) + (x-4)5 = (3/x-4)(x-4)<BR>\n" );
document.write( "1 + 5(x-4) = 3<BR>\n" );
document.write( "1 + 5x - 20 = 3<BR>\n" );
document.write( "5x = 22<BR>\n" );
document.write( "x = 22/5<BR>\n" );
document.write( "x = 4.4 </SPAN>\n" );
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