document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=677632>Question 677632</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the area contained between three circles of radius 20 centimeters, each of which is externally tangent to the other two. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #420995 by </B><A HREF=/tutors/aboutme.mpl?userid=sachi><B>sachi(548)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sachi><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=sachi><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=420995\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the circles are externally tangent to the other two.\r<BR>\n" );
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document.write( "the lines joining the centers of the circles forms an equilateral triangle with sides = 2* radius=40 cms & the area of the triangle= (sqrt3/4)*40^2=692.8 cm sqr\r<BR>\n" );
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document.write( "the two radii of the circle form a sector with angl 60 degree\r<BR>\n" );
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document.write( "the area of the 3 sectors=3*(60/360)(pi radius^2) =3/6*22/7*20^2=628.57 cm sqr\r<BR>\n" );
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document.write( "the area contained between three circles of radius <BR>\n" );
document.write( "=the area of the triangle-the area of the 3 sectors<BR>\n" );
document.write( "=692.8-628.57=64.23cm sqr<BR>\n" );
document.write( "ans </SPAN>\n" );
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