document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=677657>Question 677657</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In the parallelogram ABCD, AB=3 cm and AD=2cm. The distance between AB and CD is 1cm. Find the distance between AD and BC. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #420992 by </B><A HREF=/tutors/aboutme.mpl?userid=sachi><B>sachi(548)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sachi><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=sachi><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=420992\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the area of a parallelogram is base * height<BR>\n" );
document.write( "so taking AB as base area of parallelogram= AB*distance betn AB & CD=3*1=3....1<BR>\n" );
document.write( "now taking AD as base area of parallelogram= AD*distance betn AD & BC<BR>\n" );
document.write( "=2*distance betn AD & BC................2<BR>\n" );
document.write( "equating the above two eqns<BR>\n" );
document.write( "so 2*distance betn AD & BC=3<BR>\n" );
document.write( "or distance betn AD & BC=3/2<BR>\n" );
document.write( "ans </SPAN>\n" );
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