document.write( "Question 61142: A 15FT LADDER LEANS AGAINST A BULIDING. THE BOTTOM OF THE LADDER IS 7FT FROM THE BUILDING.HOW HIGH IS THE TOP OF THE LADDER?ROUND TO 2 DECIMAL PLACES. \n" ); document.write( "
Algebra.Com's Answer #42097 by jai_kos(139)\"\" \"About 
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A
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\n" ); document.write( "\n" ); document.write( "Let AB be the building, AC be the ladder and \r
\n" ); document.write( "\n" ); document.write( "BC is the distance between feet of ladder to the foot of the building.\r
\n" ); document.write( "\n" ); document.write( "Given the height of the ladder = 15ft\r
\n" ); document.write( "\n" ); document.write( "The distance between feet of ladder to the foot of the building = 7ft.\r
\n" ); document.write( "\n" ); document.write( "Using Pythagoras theorem, we find the length of the building which is AB.\r
\n" ); document.write( "\n" ); document.write( "AC^2 = AB^2 + BC^2\r
\n" ); document.write( "\n" ); document.write( "15 ^2 = AB^2 + 7^2\r
\n" ); document.write( "\n" ); document.write( "225 = AB^2 + 49\r
\n" ); document.write( "\n" ); document.write( "225 -49 = AB^2\r
\n" ); document.write( "\n" ); document.write( "176 = AB^2\r
\n" ); document.write( "\n" ); document.write( "Taking the square root, we get\r
\n" ); document.write( "\n" ); document.write( "13.26 = AB\r
\n" ); document.write( "\n" ); document.write( "Therefore the length of the building is 13.26 feet.
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