document.write( "Question 677481: When working together worker A and worker B take 8 hours to complete a project.Today they decide to work on the project separately. Worker A firsts works on the project for 6 hours,and then worker B finishes it in 12 hours. If worker A or worker B did the project alone, how long would it take for each of them to complete it?\r
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Algebra.Com's Answer #420913 by ankor@dixie-net.com(22740)\"\" \"About 
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When working together worker A and worker B take 8 hours to complete a project.
\n" ); document.write( "Today they decide to work on the project separately.
\n" ); document.write( "Worker A firsts works on the project for 6 hours,and
\n" ); document.write( "then worker B finishes it in 12 hours.
\n" ); document.write( " If worker A or worker B did the project alone, how long would it take for each of them to complete it?
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\n" ); document.write( "let the completed job = 1
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\n" ); document.write( "Working together
\n" ); document.write( "\"8%2FA\" + \"8%2FB\" = 1
\n" ); document.write( ":
\n" ); document.write( "Working separately
\n" ); document.write( "\"6%2FA\" + \"12%2FB\" = 1
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\n" ); document.write( "Multiply the 1st equation by 3, the 2nd equation by 2
\n" ); document.write( "\"24%2FA\" + \"24%2FB\" = 3
\n" ); document.write( "\"12%2FA\" + \"24%2FB\" = 2
\n" ); document.write( "----------------------------Subtraction eliminates B, find A
\n" ); document.write( "\"12%2FA\" = 1
\n" ); document.write( "A = 12 hrs alone
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\n" ); document.write( "Use the 1st original equation to find B, replace A with 12
\n" ); document.write( "\"8%2F12\" + \"8%2FB\" = 1
\n" ); document.write( "multiply by 12B
\n" ); document.write( "8B + 12(8) = 12B
\n" ); document.write( "96 = 12B - 8B
\n" ); document.write( "96 = 4B
\n" ); document.write( "B = 96/4
\n" ); document.write( "B = 24 hrs alone
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\n" ); document.write( "Confirm this in the 2nd original equation
\n" ); document.write( "\"6%2F12\" + \"12%2F24\" = 1
\n" ); document.write( ".5 + .5 = 1
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