document.write( "Question 677433: solve:
\n" ); document.write( "[the square root of (x-3)] +5=x
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Algebra.Com's Answer #420891 by ReadingBoosters(3246)\"\" \"About 
You can put this solution on YOUR website!
\"sqrt%28x-3%29+%2B+5+=+x\"
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\n" ); document.write( "\"sqrt%28x-3%29+=+x-5\"
\n" ); document.write( "...
\n" ); document.write( "\"sqrt%28x-3%29%5E2+=+%28x-5%29%5E2\"
\n" ); document.write( "...
\n" ); document.write( "x-3 = \"x%5E2+-+10x+%2B+25\"
\n" ); document.write( "0 = \"x%5E2+-+10x+%2B+25+-x+%2B+3\"
\n" ); document.write( "0 = \"x%5E2+-+11x+%2B+28\"
\n" ); document.write( "0 = (x-4)(x-7)
\n" ); document.write( "...
\n" ); document.write( "x-4=0, so \"highlight_green%28x=4%29\"
\n" ); document.write( "AND
\n" ); document.write( "x-7=0, so \"highlight_green%28x=7%29\"
\n" ); document.write( ".....................
\n" ); document.write( "Delighted to help.
\n" ); document.write( "-Reading Boosters
\n" ); document.write( "Website: www.MyHomeworkAnswers.com
\n" ); document.write( "Wanting for others what we want for ourselves.
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