document.write( "Question 677414: the length of a rectangle is 10 centimeters less than twice its width. The perimeter of the rectangle is 58 cm. what are the demensions of the rectangle? \n" ); document.write( "

Algebra.Com's Answer #420883 by ReadingBoosters(3246) $\"\"$ $\"About$

You can put this solution on YOUR website!
l = 2w-10
\n" ); document.write( "p = 58 = 2l+2w
\n" ); document.write( "...
\n" ); document.write( "2(2w-10) + 2w = 58
\n" ); document.write( "4w - 20 + 2w = 58
\n" ); document.write( "...
\n" ); document.write( "6w - 20 = 58
\n" ); document.write( "6w = 58 + 20
\n" ); document.write( "6w = 78
\n" ); document.write( " $\"highlight_green%28w+=+13%29\"$
\n" ); document.write( "...
\n" ); document.write( "l = 2(13)-10 = 26-10 = $\"highlight_green%28l=16%29\"$
\n" ); document.write( ".....................
\n" ); document.write( "Delighted to help.
\n" ); document.write( "-Reading Boosters
\n" ); document.write( "Website: www.MyHomeworkAnswers.com
\n" ); document.write( "Wanting for others what we want for ourselves. \n" ); document.write( "

\n" );