document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=61139>Question 61139</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve for x:   radical sign x-4= x-10   (the sign is over x-4 only)I got x=13 x=-8, but the -8 was extraneous....am i correct??? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #42086 by </B><A HREF=/tutors/aboutme.mpl?userid=asha><B>asha(30)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=asha><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=42086\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> radical sign x-4 =x-10<BR>\n" );
document.write( "squaring both the sides we get<BR>\n" );
document.write( "x-4 = (x-10)^2<BR>\n" );
document.write( "x-4 = x^2-20x+100<BR>\n" );
document.write( "taking all the terms to one side,we get<BR>\n" );
document.write( "x^2-20x-x+100+4<BR>\n" );
document.write( "x^2-21x+104<BR>\n" );
document.write( "splitting the middle term so that sum is -21 and product is 104<BR>\n" );
document.write( "we get the factors -8 and -13<BR>\n" );
document.write( "x^2-8x-13x+104=0<BR>\n" );
document.write( "x(x-8)-13(x-8)=0<BR>\n" );
document.write( "(X-8)(x-13)=0<BR>\n" );
document.write( "x=8 and x=13 are the solutions<BR>\n" );
document.write( "good luck!!! </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );