document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=60943>Question 60943</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0495012661/algebrahomeworkh>College Algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> I haven't been successfull figuring this one out.  Can anyone help?\r<BR>\n" );
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document.write( "2x + y = 0\r<BR>\n" );
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document.write( "x + 1.5y = 4.5\r<BR>\n" );
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document.write( "Solve the system of linear equations.  Thank You! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #42084 by </B><A HREF=/tutors/aboutme.mpl?userid=jai_kos><B>jai_kos(139)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jai_kos><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=42084\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Given 2x + y      = 0                &#61664;(1)<BR>\n" );
document.write( "       x + 1.5 y  = 4.5              &#61664;(2)\r<BR>\n" );
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document.write( "Consider equation (1), \r<BR>\n" );
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document.write( "2x + y = 0\r<BR>\n" );
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document.write( "2x = -y\r<BR>\n" );
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document.write( "Divide by “-1”,\r<BR>\n" );
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document.write( "-2x = y                                      &#61664;(3)\r<BR>\n" );
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document.write( "Substitute equation (3) in equation (2), we get\r<BR>\n" );
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document.write( "x + (1.5) * (-2x) = 4.5\r<BR>\n" );
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document.write( "x - 3.00x = 4.5\r<BR>\n" );
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document.write( "- 2 x = 4.5\r<BR>\n" );
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document.write( "x = 4.5 / -2 = -2.25 \r<BR>\n" );
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document.write( "Now substitute for x = -2.25 in equation (3),\r<BR>\n" );
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document.write( "-2( -2.25) = y\r<BR>\n" );
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document.write( "4.5 = y\r<BR>\n" );
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document.write( "Therefore  the value of x = -2.25 and the value of y = 4.5\r<BR>\n" );
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document.write( " </SPAN>\n" );
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