document.write( "Question 677301: The perimeter of a rectangle is 54 ft , and the area of the rectangle is 72 ft^2 . Find the dimensions of the rectangle. I need the length and width \n" ); document.write( "
Algebra.Com's Answer #420818 by aaronwiz(69)\"\" \"About 
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set up a system of equations
\n" ); document.write( "x=width
\n" ); document.write( "y=length\r
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\n" ); document.write( "\n" ); document.write( "x+y=54
\n" ); document.write( "xy=72\r
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\n" ); document.write( "\n" ); document.write( "x+y=54
\n" ); document.write( "x=72/y\r
\n" ); document.write( "\n" ); document.write( "substitute...\r
\n" ); document.write( "\n" ); document.write( "72/y+y=54\r
\n" ); document.write( "\n" ); document.write( "multiply both sides by y to remove denominator\r
\n" ); document.write( "\n" ); document.write( "72+y^2=54y\r
\n" ); document.write( "\n" ); document.write( "y^2-54y+72=0\r
\n" ); document.write( "\n" ); document.write( "now use any method of your choice to solve for y (length)... factor, quadratic equation, complete the square. Plug your answer back into the original equation to solve for x
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