document.write( "Question 677301: The perimeter of a rectangle is 54 ft , and the area of the rectangle is 72 ft^2 . Find the dimensions of the rectangle. I need the length and width \n" ); document.write( "

Algebra.Com's Answer #420817 by partha_ban(41) $\"\"$ $\"About$

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2*(l+w) = 54
\n" ); document.write( "or, l+w = 54/2 = 27
\n" ); document.write( "or, l = 27 - w
\n" ); document.write( "Now, lw=72
\n" ); document.write( "By substituting l, (27-w)*w = 72
\n" ); document.write( " $\"27w+-+w%5E2+=+72\"$
\n" ); document.write( " $\"0+=+72+-+27w+%2B+w%5E2\"$
\n" ); document.write( " $\"w%5E2+-+27w+%2B+72+=+0\"$
\n" ); document.write( "By middle term factor,
\n" ); document.write( " $\"w%5E2+-+24w+-+3w+%2B+72+=+0\"$
\n" ); document.write( " $\"w%2A%28w-24%29+-+3%28w-24%29+=+0\"$
\n" ); document.write( " $\"%28w-24%29%2A%28w-3%29=0\"$
\n" ); document.write( "Either, w-24=0 => w=24
\n" ); document.write( "OR, w-3=0 => w=3
\n" ); document.write( "If w=24, l = 27-24 = 3
\n" ); document.write( "If w=3, l = 27-3 = 24
\n" ); document.write( "Therefore length = 24 ft and width = 3 ft \n" ); document.write( "

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