document.write( "Question 677294: Is it possible to have a regular polygon with an angle measure of 18˚? \n" ); document.write( "
Algebra.Com's Answer #420810 by jim_thompson5910(35256)\"\" \"About 
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I = (180(n-2))/n\r
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\n" ); document.write( "\n" ); document.write( "18 = (180(n-2))/n\r
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\n" ); document.write( "\n" ); document.write( "18n = 180(n-2)\r
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\n" ); document.write( "\n" ); document.write( "18n = 180n-360\r
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\n" ); document.write( "\n" ); document.write( "18n - 180n = -360\r
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\n" ); document.write( "\n" ); document.write( "-162n = -360\r
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\n" ); document.write( "\n" ); document.write( "n = -360/(-162)\r
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\n" ); document.write( "\n" ); document.write( "n = 2.22222222222222\r
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\n" ); document.write( "\n" ); document.write( "Since the answer is a decimal number, when it *should* be a whole number, this means that it is impossible to have a regular polygon with an interior angle measure of 18 degrees.
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