document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=677232>Question 677232</A>: <I><SPAN STYLE=\"word-break: break-all;\"> i have 2 questions\r<BR>\n" );
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document.write( "question 1: The manager of a coffee shop has one type of coffee that sells for $5 per pound and another type that sells for $11 per pound. the manager wishes to mix 70 pounds of the $11 coffee to get a mixture that will sell for $7 per pound. How many pounds of the $5 coffee should be used?\r<BR>\n" );
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document.write( "question 2: A chemist need 60 milliliters of a 45% solution but has only 35% and 65% solutions available. Find how many milliliters of each that should be mixed to get the desired solution </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #420759 by </B><A HREF=/tutors/aboutme.mpl?userid=partha_ban><B>partha_ban(41)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=partha_ban><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=partha_ban><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=420759\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> IN FUTURE PUT QUESTIONS SEPARATELY<BR>\n" );
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document.write( "A1. Let x lb of $5 coffee is used.<BR>\n" );
document.write( "Cost of 70 lb of $11 coffee = $70 * 11 = $770<BR>\n" );
document.write( "Cost of x lb of $5 coffee = $5x<BR>\n" );
document.write( "Total cost = 770 + 5x<BR>\n" );
document.write( "Total weight = (x+70) lb<BR>\n" );
document.write( "Cost of (x+70) lb of $7 coffee = (x+70)*7 = 7x + 490<BR>\n" );
document.write( "By condition, 7x + 490 = 770 + 5x<BR>\n" );
document.write( "7x - 5x = 770 - 490<BR>\n" );
document.write( "2x = 280<BR>\n" );
document.write( "x = 280 / 2 = 140 lb<BR>\n" );
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document.write( "A2. Let x ml of 35% solution has been mixed with y ml of 65% solution to get (x+y) ml of 45% solution<BR>\n" );
document.write( "Therefore, x*35/100 + y*65/100 = (x+y)*45/100<BR>\n" );
document.write( "or, (35x + 65y)/100 = (45x+45y)/100<BR>\n" );
document.write( "or, 35x + 65y = 45x + 45y<BR>\n" );
document.write( "or, 35x - 45x = 45y - 65y<BR>\n" );
document.write( "or, -10x = -20y<BR>\n" );
document.write( "or, x/y = (-20)/(-10)<BR>\n" );
document.write( "or, x/y = 2/1<BR>\n" );
document.write( "Therefore the ration between 35% solution and 65% solution should be 2:1. </SPAN>\n" );
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