document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=677235>Question 677235</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A picture frame has a length that is 2 inches more than its width. if the area of the frame is 35 square inches, find the dimensions of the frame? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #420758 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=420758\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Area(A)equals Length(L) times Width(W) or A=LW\r<BR>\n" );
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document.write( "Let W=width of frame<BR>\n" );
document.write( "Then L=W+2<BR>\n" );
document.write( "Sooooo<BR>\n" );
document.write( "35=(W+2)*W<BR>\n" );
document.write( "35=W^2+2W<BR>\n" );
document.write( "W^2+2W-35=0  quadratic in standard form and it can be factored<BR>\n" );
document.write( "(W+7)(W-5)=0<BR>\n" );
document.write( "W=-7----------------No good. Dimensions should be positive.<BR>\n" );
document.write( "W=5---------------------width of frame<BR>\n" );
document.write( "W+2=5+2=7----------------length of frame<BR>\n" );
document.write( "CK<BR>\n" );
document.write( "35=5*7<BR>\n" );
document.write( "35=35\r<BR>\n" );
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document.write( "Hope this helps---ptaylor </SPAN>\n" );
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