document.write( "Question 677182: Randy Invested twice as much at 10% as he did at 8%. If he earned $30.80 annually, how much did he invest at each rate? \n" ); document.write( "

Algebra.Com's Answer #420739 by josmiceli(19441) $\"\"$ $\"About$

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Let $\"+x+\"$ = amount invest @ 8%
\n" ); document.write( " $\"+2x+\"$ = amount invested @ 10%
\n" ); document.write( "given:
\n" ); document.write( " $\"+.08x+%2B+.1%2A%282x%29+=+30.8+\"$
\n" ); document.write( " $\"+.08s+%2B+.2x+=+30.8+\"$
\n" ); document.write( " $\"+.28x+=+30.8+\"$
\n" ); document.write( " $\"+x+=+110+\"$
\n" ); document.write( " $\"+2x+=+220+\"$
\n" ); document.write( "Randy invested $110 @8% and $220 @10%
\n" ); document.write( " \n" ); document.write( "

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