document.write( "Question 7618: If 5 apples and 4 oranges cost $3.40 while 7 apples and 6 oranges cost $4.90.Find the cost of an apple and an orange. \n" ); document.write( "

Algebra.Com's Answer #4207 by prabhjyot(165) $\"\"$ $\"About$

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In the problem we have to find price of one apple and one orange
\n" ); document.write( "Let cost of apple be x and cost of orange be y
\n" ); document.write( "Now given 5 apples and 4 oranges cost $3.40
\n" ); document.write( "so we get
\n" ); document.write( "5x +4y=3.4 ------>(1)\r
\n" ); document.write( "\n" ); document.write( "7 apples and 6 oranges cost $4.90\r
\n" ); document.write( "\n" ); document.write( "7x + 6y=4.9 ---->(2)\r
\n" ); document.write( "\n" ); document.write( "Now we have two linear equation,we solve these equations using substituion method
\n" ); document.write( "from equation (1) we get
\n" ); document.write( " $\"x+=+%283.4+-4y%29%2F5\"$ --->(3)\r
\n" ); document.write( "\n" ); document.write( "Substituting the above equation (3)into the second equation:\r
\n" ); document.write( "\n" ); document.write( " $\"7%283.4%2B4y%29%2F5%2B6y+=+4.9\"$ \r
\n" ); document.write( "\n" ); document.write( "y = 0.35
\n" ); document.write( "Now, put y = 0.35 into equation(3)\r
\n" ); document.write( "\n" ); document.write( " $\"x+=+%283.4-4%280.35%29%29%2F5+=+0.4\"$
\n" ); document.write( "So x=0.4
\n" ); document.write( "y=0.35
\n" ); document.write( "So cost of one apple = x= $0.4
\n" ); document.write( "and cost of one orange = y=$ 0.35\r
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