document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=677102>Question 677102</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A man invests his savings in 2 accounts, one paying 6% per year<BR>\n" );
document.write( "and the other 7%. He has twice as much invested in the 7% account<BR>\n" );
document.write( "as in the 6% account, and his annual interest income is $600. How<BR>\n" );
document.write( "much is invested in each account? I=PRT </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #420687 by </B><A HREF=/tutors/aboutme.mpl?userid=partha_ban><B>partha_ban(41)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=partha_ban><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=partha_ban><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=420687\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let he put $d in 6% interest account (1st account)<BR>\n" );
document.write( "So, he put $2d in 7% interest account (2nd account)\r<BR>\n" );
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document.write( "Interest earned from 1st account = d * (6/100) * 1 = 6d/100<BR>\n" );
document.write( "Interest earned from 2nd account = 2d * (7/100) * 1 = 14d/100\r<BR>\n" );
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document.write( "Total interest earned = 6d/100 + 14d/100 = (6d+14d)/100 = 20d/100 = d/5\r<BR>\n" );
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document.write( "By condition, d/5 = 600<BR>\n" );
document.write( "Therefore, d = 600 * 5 = 3,000\r<BR>\n" );
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document.write( "Therefore, the man invested $3,000 in 6% interest account and $6,000 in 7% interest account. </SPAN>\n" );
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