document.write( "Question 61100: Instructions: Solve each system by the substitution method.\r
\n" ); document.write( "\n" ); document.write( "What is the solution for 3x+y=-7
\n" ); document.write( " x-y=-5
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Algebra.Com's Answer #42046 by jai_kos(139)\"\" \"About 
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Solution:\r
\n" ); document.write( "\n" ); document.write( "Given \r
\n" ); document.write( "\n" ); document.write( "3x + y = -7 (1)
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\n" ); document.write( "x - y = -5 (2)\r
\n" ); document.write( "\n" ); document.write( "Consider equation (2), we can rewrite the equation (2) as\r
\n" ); document.write( "\n" ); document.write( "x + 5 = y (3)\r
\n" ); document.write( "\n" ); document.write( "Substitute the equation (3) in equation (1), we get\r
\n" ); document.write( "\n" ); document.write( "3x + (x + 5) = - 7\r
\n" ); document.write( "\n" ); document.write( "3x + x + 5 = -7\r
\n" ); document.write( "\n" ); document.write( "4x + 5 = -7\r
\n" ); document.write( "\n" ); document.write( "4x = - 7 – 5\r
\n" ); document.write( "\n" ); document.write( "4x = -12\r
\n" ); document.write( "\n" ); document.write( "x = -12 / 4\r
\n" ); document.write( "\n" ); document.write( "x = -3 (4)\r
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\n" ); document.write( "\n" ); document.write( "Put x = -3 in equation (1), we get\r
\n" ); document.write( "\n" ); document.write( "3(-3) + y = -7\r
\n" ); document.write( "\n" ); document.write( "-9 + y = - 7\r
\n" ); document.write( "\n" ); document.write( "y = - 7 + 9\r
\n" ); document.write( "\n" ); document.write( "y = 2\r
\n" ); document.write( "\n" ); document.write( "Therefore the value of x = -3 and y = 2 \r
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