document.write( "Question 676634: sally lives in chicago rocky lives in ohio 315 kilometers apart sally rides her motorcycle at 115 km/hr rocky can ride his at 60km/hr they leave at same time in how hours will they meet \n" ); document.write( "
Algebra.Com's Answer #420441 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
Distance(d) equals Rate(r) times Time(t) or d=rt; r=d/t and t=d/r
\n" ); document.write( "They meet when they are both the same distance from Chicago. Let t=time it takes for that to happen
\n" ); document.write( "distance that Rocky is from Chi in t hours=315-60t
\n" ); document.write( "distance that Sally is from Chi in t hours= 115t\r
\n" ); document.write( "\n" ); document.write( "Soooooo
\n" ); document.write( "315-60t=115t
\n" ); document.write( "175t=315
\n" ); document.write( "t=1.8 hrs\r
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "in 1.8 hrs, Rocky has traveled 60*1.8=108 mi and is 315-108=207 mi from Chicago
\n" ); document.write( "in 1.8 hrs, Sally has traveled 115*1.8 mi=207 mi and is 207 mi from Chicago\r
\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );