document.write( "Question 676511: A and B play for a prize to win 1000 Birr. A is to throw a die first and to win if he throws 6. If A fails, B is to throw and to win if he throws 5 or 6. If B fails, A is to throw again to win if throws 4, 5 or 6, and so on.
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Algebra.Com's Answer #420408 by edjones(8007)\"\" \"About 
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1st throw: 1/6 probability A wins
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\n" ); document.write( "2nd: 1- 1/6 = 5/6
\n" ); document.write( "5/6 * 2/6 = 5/18 prob B wins
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\n" ); document.write( "3rd 1-(1/6 + 5/18)=5/9
\n" ); document.write( "5/9 * 3/6 = 5/18 prob A wins
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\n" ); document.write( "4th 1-(1/6 + 5/18 + 5/18)=5/18
\n" ); document.write( "5/18 * 4/6 =5/27 prob B wins
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\n" ); document.write( "5th 1-(1/6 + 5/18 + 5/18 + 5/27)=5/54
\n" ); document.write( "5/54 * 5/6 = 25/324 Prob A wins
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\n" ); document.write( "1-(1/6 + 5/18 + 5/18 + 5/27 + 25/324)=5/324 prob B wins.
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\n" ); document.write( "1/6 + 5/18 + 25/324 = 169/324 the total probabilities of A’s success.
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