document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=676495>Question 676495</A>: <I><SPAN STYLE=\"word-break: break-all;\"> two cars leave the same point at the same time one car is traveling 1 1/3 times as fast as the other after 3 hrs they are 45 miles apart. what speed is each car going? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #420356 by </B><A HREF=/tutors/aboutme.mpl?userid=jpvn2015><B>jpvn2015(54)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jpvn2015><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=420356\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 60 mph and 45 mph. \r<BR>\n" );
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document.write( "Here's how I came up with that answer. First, realize that 45 miles over a period of 3 hours, is equivalent with 15 miles over 1 hour. Thus, one car was going 15 mph faster than the other car and was also going 4/3 its speed. \r<BR>\n" );
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document.write( "60 and 45 meet those criteria perfectly, as 60 is 15 greater than 45, and over a period of 3 hours, the car going 60mph will be 45 miles further on the road than the car going 45 mph. Plus, 60 is 1 1/3 greater than 45, so it verifies that this is indeed the correct answer.  </SPAN>\n" );
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