document.write( "Question 676344: Write a polynomial function f(x), in standard form, of the least degree that has real coefficients, the given zeros (3, -4, 2+[square root of 5]), and a leading coefficient of 1. \n" ); document.write( "
Algebra.Com's Answer #420306 by ReadingBoosters(3246)\"\" \"About 
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x = 3, so x-3 = 0
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\n" ); document.write( "x = -4, so x+4=0
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\n" ); document.write( "x = \"2%2Bsqrt%285%29\", so x - 2 = \"sqrt%285%29\"; therefore, \"%28x-2%29%5E2=5\", so \"%28x-2%29%5E2+-+5+=+0\"
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\n" ); document.write( "\"%28x-3%29%28x%2B4%29%28x-2%29%5E2-5+=+0\"
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\n" ); document.write( "Foil (x-3)(x+4)
\n" ); document.write( "Foil (x-2)(x-2)
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\n" ); document.write( "\"%28x%5E2%2B4x-3x-12%29%28x%5E2-4x%2B4%29-5=0\"
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\n" ); document.write( "\"%28x%5E2%2Bx-12%29%28x%5E2-4x%2B4%29-5=0\"
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\n" ); document.write( "\"x%5E4+-+4x%5E3+%2B+4x%5E2+%2B+x%5E3+-+4x%5E2+%2B+4x+-+12x%5E2+%2B+48x+-+48+-+5+=0\"
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\n" ); document.write( "\"highlight_green%28x%5E4+-+3x%5E3+-+12x%5E2+%2B+52x+-+53=0%29\"
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