document.write( "Question 676270: Jim leaves 25 miles from work. He rides his bike at 9mph to the metro which travels at 30mph. He spends 2 minutes less on his bike than on the metro. What's the distance from his house to the metro? \r
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document.write( "The answer is five miles. However, here is how I set it up. 9(x-2) + 30x = 25 and then I tried 9(x-.03) + 30x = 25. Not once did I get the answer. I'm stuck. \n" );
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Algebra.Com's Answer #420295 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! Jim leaves 25 miles from work. \n" ); document.write( " He rides his bike at 9mph to the metro which travels at 30mph. \n" ); document.write( " He spends 2 minutes less on his bike than on the metro. \n" ); document.write( " What's the distance from his house to the metro? \n" ); document.write( ": \n" ); document.write( "I don't get that answer either, but because we are using mph, you have to convert two minutes to hrs. \n" ); document.write( ": \n" ); document.write( "let = time to bike to the metro at 9 mph \n" ); document.write( "Change two min to hrs: 2/60 = 1/30 hr \n" ); document.write( "then \n" ); document.write( "(t+ \n" ); document.write( ": \n" ); document.write( "WRite a diat equation; dist = speed * time \n" ); document.write( ": \n" ); document.write( "bike dist + metro dist = 25 mi \n" ); document.write( "9t + 30(t+ \n" ); document.write( "9t + 30t + 1 = 25; (30's cancel) \n" ); document.write( "39t = 25 - 1 \n" ); document.write( "39t = 24 \n" ); document.write( "t = 24/39 = 8/13 hrs on the bike \n" ); document.write( "Find the dist \n" ); document.write( "9* \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check this by finding the distance on the metro \n" ); document.write( "[ \n" ); document.write( ".6487 * 30 = 19.46 mi on the bus \n" ); document.write( ": \n" ); document.write( "Find the total distances of bike and bus \n" ); document.write( "5.54 + 19.46 = 25 mi, confirms our solution of 5.54 to the metro \n" ); document.write( " |