document.write( "Question 676270: Jim leaves 25 miles from work. He rides his bike at 9mph to the metro which travels at 30mph. He spends 2 minutes less on his bike than on the metro. What's the distance from his house to the metro? \r
\n" ); document.write( "\n" ); document.write( "The answer is five miles. However, here is how I set it up. 9(x-2) + 30x = 25 and then I tried 9(x-.03) + 30x = 25. Not once did I get the answer. I'm stuck.
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Algebra.Com's Answer #420295 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Jim leaves 25 miles from work.
\n" ); document.write( " He rides his bike at 9mph to the metro which travels at 30mph.
\n" ); document.write( " He spends 2 minutes less on his bike than on the metro.
\n" ); document.write( " What's the distance from his house to the metro?
\n" ); document.write( ":
\n" ); document.write( "I don't get that answer either, but because we are using mph, you have to convert two minutes to hrs.
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\n" ); document.write( "let = time to bike to the metro at 9 mph
\n" ); document.write( "Change two min to hrs: 2/60 = 1/30 hr
\n" ); document.write( "then
\n" ); document.write( "(t+\"1%2F30\") = time on the metro at 30 mph
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\n" ); document.write( "WRite a diat equation; dist = speed * time
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\n" ); document.write( "bike dist + metro dist = 25 mi
\n" ); document.write( "9t + 30(t+\"1%2F30\") = 25
\n" ); document.write( "9t + 30t + 1 = 25; (30's cancel)
\n" ); document.write( "39t = 25 - 1
\n" ); document.write( "39t = 24
\n" ); document.write( "t = 24/39 = 8/13 hrs on the bike
\n" ); document.write( "Find the dist
\n" ); document.write( "9*\"8%2F13\" = 5.54 miles to the metro
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\n" ); document.write( "Check this by finding the distance on the metro
\n" ); document.write( "[\"8%2F13\"+\"1%2F30\"] * 30 =
\n" ); document.write( ".6487 * 30 = 19.46 mi on the bus
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\n" ); document.write( "Find the total distances of bike and bus
\n" ); document.write( "5.54 + 19.46 = 25 mi, confirms our solution of 5.54 to the metro
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