document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=676329>Question 676329</A>: <I><SPAN STYLE=\"word-break: break-all;\"> factor completely: g(x)= -1/4(x^4-x^3-5x^2-x-6) If g(3)=0 and g(4)= -25 1/2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #420289 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=420289\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> factor completely: g(x)= -1/4(x^4-x^3-5x^2-x-6) If g(3)=0 and g(4)= -25 1/2<BR>\n" );
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document.write( "Since g(3) = 0, x-3 is a factor of g(x)<BR>\n" );
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document.write( "3)....1....-1....-5....-1....-6<BR>\n" );
document.write( "......1....2.....1.....2...|..0\r<BR>\n" );
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document.write( "Quotient: x^3+2x^2+x+2<BR>\n" );
document.write( "= x^2(x+2)+(x+2)<BR>\n" );
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document.write( "= (x+2)(x^2+1)<BR>\n" );
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document.write( "g(x) = (-1/4)(x-3)(x+2)(x^2+1)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "stan H.<BR>\n" );
document.write( " </SPAN>\n" );
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