document.write( "Question 61016This question is from textbook as pure mathematics
\n" ); document.write( ": a cylindrical tin of particular volume is to be made using as little material as possible. find the ratio of the height to the radius(the tin is closed both ends) \n" ); document.write( "
Algebra.Com's Answer #42024 by venugopalramana(3286)\"\" \"About 
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a cylindrical tin of particular volume is to be made using as little material as possible. find the ratio of the height to the radius(the tin is closed both ends)
\n" ); document.write( "LET THE RATIO OF HEIGHT TO RADIUS = X =H/R.....H=RX
\n" ); document.write( "VOLUME OF CYLINDER = PI*(R^2)*H = V = CONSTANT.
\n" ); document.write( "V = PI*R^2*RX = PI*(R^3)*X
\n" ); document.write( "R=[V/(PI*X)]^(1/3)
\n" ); document.write( "A = AREA OF CYLINDER = 2PI*R*H+2PI*R^2=2PI*R[RX+R]=2PI*(R^2)[X+1]
\n" ); document.write( "A = 2PI*R^2[X+1]=2PI[X+1][V/(PI*X)]^(2/3)
\n" ); document.write( "A=[2PI*V^(2/3)/{PI}^(2/3)][(X+1)/X^(2/3)]
\n" ); document.write( "A = K[X^(1/3)+X^(-2/3)]
\n" ); document.write( "DA/DX = 0 FOR MINIMUM VALUE = K[(1/3){X^(-2/3)} -(2/3){X^(-5/3)}]=0
\n" ); document.write( "1/3{X^(2/3)}= 2/3{X^(5/3)}
\n" ); document.write( "X^(5/3)/X^(2/3)=2
\n" ); document.write( "X = 2
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