document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=676223>Question 676223</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the absolute extreme values of f(x)=3x^5-15x^4-25x^3 on the interval [-2,3]\r<BR>\n" );
document.write( "\n" );
document.write( "please help! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #420237 by </B><A HREF=/tutors/aboutme.mpl?userid=swincher4391><B>swincher4391(1107)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=swincher4391><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=swincher4391><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=420237\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Take the derivative to get 15x^4 - 60x^3 - 75x^2\r<BR>\n" );
document.write( "\n" );
document.write( "Factor out a 15x^2 to get  x^2-4x-5 This factors into 15x^2(x-5)(x+1).\r<BR>\n" );
document.write( "\n" );
document.write( "Then  you would get 0,-1,5 are your critical points. But 0 and -1 are the only things on your interval.\r<BR>\n" );
document.write( "\n" );
document.write( "Then you plug in the end points:\r<BR>\n" );
document.write( "\n" );
document.write( "f(-2) = -136<BR>\n" );
document.write( "f(3) = -1161\r<BR>\n" );
document.write( "\n" );
document.write( "And then plug in your critical values:\r<BR>\n" );
document.write( "\n" );
document.write( "f(-1) = 7<BR>\n" );
document.write( "f(0) = 0\r<BR>\n" );
document.write( "\n" );
document.write( "Then 7 is your absolute maximum and  -1161 is your minimum. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );