document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=676198>Question 676198</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 4. M is between L and N. ML = 4x – 12. MN = x + 2. LN = 40. Find LM. <BR>\n" );
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document.write( "A. 	 10<BR>\n" );
document.write( "B. 	 12<BR>\n" );
document.write( "C. 	 28<BR>\n" );
document.write( "D. 	 32<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #420218 by </B><A HREF=/tutors/aboutme.mpl?userid=jpvn2015><B>jpvn2015(54)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jpvn2015><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=420218\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The answer is C, 28. Here is how I got it: \r<BR>\n" );
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document.write( "If LN = 40, then 40 must equal LM+ MN or 4x-12+x+2.<BR>\n" );
document.write( "In other words, 40 = 4x-12+x+2 <BR>\n" );
document.write( "Combine and add like terms: 40=5x-10 <BR>\n" );
document.write( "Add ten to both sides: 50 = 5x <BR>\n" );
document.write( "Dividing both sides by 5 yields: x=10 \r<BR>\n" );
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document.write( "So, once we find x (10), we can substitute it in for LM (or ML). <BR>\n" );
document.write( "4x - 12 <BR>\n" );
document.write( "4(10) - 12 <BR>\n" );
document.write( "40-12 <BR>\n" );
document.write( "28. \r<BR>\n" );
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document.write( "Thus, C is the correct answer.  </SPAN>\n" );
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