document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=676112>Question 676112</A>: <I><SPAN STYLE=\"word-break: break-all;\"> substract 3/9 - 2/11 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #420187 by </B><A HREF=/tutors/aboutme.mpl?userid=jpvn2015><B>jpvn2015(54)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jpvn2015><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=420187\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First, we need to find the least common denominator. The LCD is 99. \r<BR>\n" );
document.write( "\n" );
document.write( "To get the first fraction to a denominator of 99, we need to multiply it by 11. Thus, the first fractions is: 33/99 \r<BR>\n" );
document.write( "\n" );
document.write( "The second needs to be multiplied by 9. Second fraction is: 18/99 \r<BR>\n" );
document.write( "\n" );
document.write( "So, the answer is: 33/99 - 18/99 or simply, 15/99. \r<BR>\n" );
document.write( "\n" );
document.write( "15/99 cannot be reduced, thus 15/99 is your answer.  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );