document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=676129>Question 676129</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please help me got this wrong on homework but do not know why! <BR>\n" );
document.write( "6(b+3)+2(b+5) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #420182 by </B><A HREF=/tutors/aboutme.mpl?userid=jpvn2015><B>jpvn2015(54)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jpvn2015><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=420182\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First, bifurcate this problem: 6(b+3)             worry about 2(b+5) later <BR>\n" );
document.write( "6(b+3) = 6b + 18. You simply multiply the 6 by the b and the 6 by the 3. <BR>\n" );
document.write( "Then, we work on the second bifurcation: 2(b+5). This equals 2b + 10 for the same reasons as the one above. \r<BR>\n" );
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document.write( "Thus, our problem now reads: 6b+18+2b+10 <BR>\n" );
document.write( "You add like figures which yields: 8b + 28\r<BR>\n" );
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document.write( "8b + 28 is the most precise you can get in this problem, so 8b+28 is your answer.  </SPAN>\n" );
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