document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=676000>Question 676000</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help with the following question: \"A man has 26 coins in his pocket, all of which are dimes and quarters. If the total value of his change is 485 cents, how many dimes and quarters does he have?\" </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #420155 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=420155\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A man has 26 coins in his pocket, all of which are dimes and quarters. If the total value of his change is 485 cents, how many dimes and quarters does he have?<BR>\n" );
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document.write( "Let x = number of dimes<BR>\n" );
document.write( "then<BR>\n" );
document.write( "26-x = number of quarters<BR>\n" );
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document.write( "10x + 25(26-x) = 485<BR>\n" );
document.write( "10x + 650-25x = 485<BR>\n" );
document.write( "650-15x = 485<BR>\n" );
document.write( "-15x = -165<BR>\n" );
document.write( "x = -165/(-15)<BR>\n" );
document.write( "x = 11 (dimes)<BR>\n" );
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document.write( "quarters:<BR>\n" );
document.write( "25-11 = 14<BR>\n" );
document.write( " </SPAN>\n" );
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