document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=676013>Question 676013</A>: <I><SPAN STYLE=\"word-break: break-all;\"> ok....Suppose that a 12 quart radiator contains a 20% solution of antifreeze. how much solution needs to be drained out and replaced with pure antifreeze to obtain a 40% solution of antifreeze.... </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #420154 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=420154\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Suppose that a 12 quart radiator contains a 20% solution of antifreeze. how much solution needs to be drained out and replaced with pure antifreeze to obtain a 40% solution of antifreeze<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Let x = amount (quarts) drained and replaced<BR>\n" );
document.write( "then<BR>\n" );
document.write( ".20(12-x) + x = .40(12)<BR>\n" );
document.write( "2.4-.20x + x = 4.8<BR>\n" );
document.write( "2.4 + .80x = 4.8<BR>\n" );
document.write( ".80x = 2.4<BR>\n" );
document.write( "x = 2.4/.80<BR>\n" );
document.write( "x = 3 quarts<BR>\n" );
document.write( " </SPAN>\n" );
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