document.write( "Question 675962: the area of a rectangle is 2x^2-11x+15 square feet. the length of the rectangle is 2x-5 feet. What is the width of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #420143 by MathLover1(20850)\"\" \"About 
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the area of a rectangle is \"A=%282x%5E2-11x%2B15%29ft%5E2\" \r
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\n" ); document.write( "\n" ); document.write( "the width \"W\" will be\r
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\n" ); document.write( "\n" ); document.write( "\"A=L%2AW\"\r
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\n" ); document.write( "\n" ); document.write( "\"W=A%2FL\"\r
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\n" ); document.write( "\n" ); document.write( "\"W=%282x%5E2-11x%2B15%29ft%5E2%2F%282x-5%29ft\".....replace \"-11x\" with \"-6x-5x\"\r
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\n" ); document.write( "\n" ); document.write( "\"W=%282x%5E2-6x-5x%2B15%29ft%2F%282x-5%29\"....group\r
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\n" ); document.write( "\n" ); document.write( "\"W=%28%282x%5E2-6x%29-%285x-15%29%29ft%2F%282x-5%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"W=%282x%28x-3%29-5%28x-3%29%29ft%2F%282x-5%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"W=%28%282x-5%29%28x-3%29%29ft%2F%282x-5%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"W=%28cross%28%282x-5%29%29%28x-3%29%29ft%2Fcross%28%282x-5%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"highlight%28W=%28x-3%29ft%29\"\r
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