document.write( "Question 61093This question is from textbook Intermediate Algebra
\n" ); document.write( ": The current in ther lazy river moves at a rate of 4mph. Monica'sdinghy motors 6mi upstream in the same time it take to motor 12mi downstream. What is the speed of the dinghy? \n" ); document.write( "
Algebra.Com's Answer #42012 by funmath(2933)\"\" \"About 
You can put this solution on YOUR website!
The current in ther lazy river moves at a rate of 4mph. Monica'sdinghy motors 6mi upstream in the same time it take to motor 12mi downstream. What is the speed of the dinghy?
\n" ); document.write( "The distance formula is d=rt. d=distance, r=rate, and t=time. Solve the formula for t.
\n" ); document.write( "\"d%2Fr=rt%2Fr\"--->\"d%2Fr=t\"
\n" ); document.write( "distance up stream=6
\n" ); document.write( "rate upstream is the rate of the boat (r)- rate of the current(4):r-4
\n" ); document.write( "distance downstream=12
\n" ); document.write( "rate downstream is the rate of the boat (r)+ rate of the current(4): r+4
\n" ); document.write( "The time is the same for both, so set the distance formula solved for time equal to each other.
\n" ); document.write( "\"6%2F%28r-4%29=12%2F%28r%2B4%29\"
\n" ); document.write( "\"6%28r-4%29%2F%28r-4%29=12%28r-4%29%2F%28r%2B4%29\"
\n" ); document.write( "\"6=12%28r-4%29%2F%28r%2B4%29\"
\n" ); document.write( "\"6%28r%2B4%29=12%28r-4%29%28r%2B4%29%2F%28r%2B4%29\"
\n" ); document.write( "\"6%28r%2B4%29=12%28r-4%29\"
\n" ); document.write( "\"6r%2B24=12r-48\"
\n" ); document.write( "\"6r-6r%2B24=12r-6r-48\"
\n" ); document.write( "\"24=6r-48\"
\n" ); document.write( "\"24%2B48=6r-48%2B48\"
\n" ); document.write( "\"72=6r\"
\n" ); document.write( "\"72%2F6=6r%2F6\"
\n" ); document.write( "\"12=r\"
\n" ); document.write( "The dingy was moving at 12 mph.
\n" ); document.write( ":
\n" ); document.write( "Happy Calculating!!!
\n" ); document.write( "
\n" );