document.write( "Question 52998: Pleas help me with this problem.
\n" ); document.write( "Roy has 8 gallons of 40% antifreeze solution. How much 100% antifreeze mus be added to make a solution that is at least 60% antifreeze.\r
\n" ); document.write( "\n" ); document.write( "Thanks =) \n" ); document.write( "
Algebra.Com's Answer #42011 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
Let x=amt of pure antifreeze that must be added\r
\n" ); document.write( "\n" ); document.write( "Solution (1)
\n" ); document.write( "Amt of pure antifreeze in the 8 gals (8)(.40) plus amt of pure antifreeze
\n" ); document.write( "added (x)(1) equals the amt of pure antifreeze in the final mixture (x+8)(.60).
\n" ); document.write( "Thus, our equation to solve is:
\n" ); document.write( "(8)(.4)+(x)(1)=(x+8)(.60) simplifying, we get:
\n" ); document.write( "3.2+x=.6x+4.8 or
\n" ); document.write( ".4x=1.6
\n" ); document.write( "x=4 gal\r
\n" ); document.write( "\n" ); document.write( "Solution (2)
\n" ); document.write( "If we assume the mixture is antifreeze and water, notice that the amt of water does not change throughout the process.
\n" ); document.write( "Amt of water in the 8 gal (8)(.60) plus the amt of water added (0)equals the amt of water in the final mixture (x+8)(.40).
\n" ); document.write( "Thus, our equation to solve is:
\n" ); document.write( "(8)(.60)=(x+8)(.40) simplifying, we get:
\n" ); document.write( "4.8=.4x+3.2 or
\n" ); document.write( ".4x=1.6
\n" ); document.write( "x=4 gal\r
\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor\r
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