document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=675896>Question 675896</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two angles are complementary. The measure of one angle is 42° more than three times the measure of the other. Find the measure of each angle<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #420104 by </B><A HREF=/tutors/aboutme.mpl?userid=ReadingBoosters><B>ReadingBoosters(3246)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ReadingBoosters><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=420104\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = one angle<BR>\n" );
document.write( "y = other angle<BR>\n" );
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document.write( "x = 42 + 3y<BR>\n" );
document.write( "x+y = 90<BR>\n" );
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document.write( "substitute x into the second equation<BR>\n" );
document.write( "42+3y + y = 90<BR>\n" );
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document.write( "combine like terms<BR>\n" );
document.write( "42 + 4y = 90<BR>\n" );
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document.write( "isolate y<BR>\n" );
document.write( "4y = 90 - 42<BR>\n" );
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document.write( "4y = 48<BR>\n" );
document.write( "divide both sides by 4<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%28y+=+12%29 ALIGN=MIDDLE  ALT=\"highlight_green%28y+=+12%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >degrees<BR>\n" );
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document.write( "x = 42 + 3y = 42 + 3(12) = 42 + 36 = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%28x=78%29 ALIGN=MIDDLE  ALT=\"highlight_green%28x=78%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > degrees<BR>\n" );
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