document.write( "Question 675805: A man spent 1/3 of his life in England, 1/4 of it in Scotland and the remainder of it, which is 40 years, in Canada. What was his age? \n" ); document.write( "

Algebra.Com's Answer #420095 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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A man spent 1/3 of his life in England, 1/4 of it in Scotland and the remainder of it, which is 40 years, in Canada.
\n" ); document.write( " What was his age?
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\n" ); document.write( "Let a = his age
\n" ); document.write( ":
\n" ); document.write( "a = $\"1%2F3\"$ a + $\"1%2F4\"$ a + 40
\n" ); document.write( "mult by 12 to get rid of the denominators, results:
\n" ); document.write( "12a = 4a + 3a + 12(40)
\n" ); document.write( "12a = 7a + 480
\n" ); document.write( "12a - 7a = 480
\n" ); document.write( "5a = 480
\n" ); document.write( "a = 480/5
\n" ); document.write( "a = 96 is his age
\n" ); document.write( ":
\n" ); document.write( "Check this:
\n" ); document.write( " $\"1%2F3\"$ *96 + $\"1%2F4\"$ *96 + 40 =
\n" ); document.write( "32 + 24 + 40 = 96
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