document.write( "Question 61081This question is from textbook Intermediate Algebra
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document.write( ": The HP officejet 6110 takes twice the time required by the Canon Imageclass D680 to photocopy brochures for the New Bretton Arts Council year-end concert. If working together the two machines can complete the job in 24min, how long would it take each machine, working alone to copy the brochures? \n" );
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Algebra.Com's Answer #42001 by uma(370)![]() ![]() ![]() You can put this solution on YOUR website! Suppose the time taken by the Canon machine to complete the job = x hrs. \n" ); document.write( "So time taken by the HP machine = 2x hrs.\r \n" ); document.write( "\n" ); document.write( "Quantity copied by the canon in 1 hr = 1/x \n" ); document.write( "Quantity copied by the HP in 1 hr = 1/2x\r \n" ); document.write( "\n" ); document.write( "Together the quantity copied in 1 hr = 1/x + 1/2x \n" ); document.write( " = (2+1)/2x [taking LCD] \n" ); document.write( " = 3/2x\r \n" ); document.write( "\n" ); document.write( "Given the time taken by both to complete the job = 24 min \n" ); document.write( "==> quantity copied in 1 hr = 1/24\r \n" ); document.write( "\n" ); document.write( "Equating we get, \n" ); document.write( "1/24 = 3/2x \n" ); document.write( "multiply both the sides by 24x(LCD), \n" ); document.write( "(1/24)(24x) = (3/2x)(24x) \n" ); document.write( "==> x = 36\r \n" ); document.write( "\n" ); document.write( "Thus the Canon takes 36 minto copy and the HP takes 36*2 = 72 min to copy.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Good Luck!!!\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |