document.write( "Question 61079This question is from textbook Intermedidaten Algebra
\n" ); document.write( ": \"Arctic Antifreeze\" is 18%alchol and \"frost No-More\" is 10%alchol. How many liters of each should be mixed to get 20L of a mixture that is 15% alchol? \n" ); document.write( "

Algebra.Com's Answer #41999 by uma(370) $\"\"$ $\"About$

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Suppose that'x' litres of 18% alcohol is taken.
\n" ); document.write( "Then quantity of 10% alcohol needed = (20 - x)litres.[as the total is 20 liters]
\n" ); document.write( "Thus the equation becomes
\n" ); document.write( "x*0.18 + (20-x)*0.10 = 20*0.15
\n" ); document.write( "==> 0.18x + 2 - 0.10x = 3
\n" ); document.write( "==> 0.08x + 2 = 3
\n" ); document.write( "==> 0.08x + 2 - 2 = 3 - 2
\n" ); document.write( "==> 0.08x = 1
\n" ); document.write( "==> 0.08x/0.08 = 1/0.08
\n" ); document.write( "==> x = 1/0.08
\n" ); document.write( "==> x = 12.5\r
\n" ); document.write( "\n" ); document.write( "So the quantity of 18% alcohol = 12.5 liters
\n" ); document.write( "The quantity of 10% alcohol = 20 - 12.5
\n" ); document.write( " = 7.5 liters\r
\n" ); document.write( "\n" ); document.write( "Thus 12.5 liters of 18% alcohol is added to 7.5 liters of 10% alcohol to arrive at 20 liters of 15% alcohol.\r
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\n" ); document.write( "\n" ); document.write( "Good Luck!!! \n" ); document.write( "

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