document.write( "Question 675613: Consider the approximately normal population of heights of male college students with mean μ = 70 inches and standard deviation of σ = 6.4 inches. A random sample of 10 heights is obtained.\r
\n" ); document.write( "\n" ); document.write( "Find the proportion of male college students whose height is greater than 72 inches. (Give your answer correct to four decimal places.\r
\n" ); document.write( "\n" ); document.write( "I have worked this out several times and still get the same answer which is incorrect. HELP. Thanks
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Algebra.Com's Answer #419979 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi
\n" ); document.write( "Re: TY, might consider, \"A random sample of 10 heights is obtained\" is not
\n" ); document.write( "what the question is in reference to.
\n" ); document.write( "\"Find the proportion of male college students whose height is greater than 72 inches\"
\n" ); document.write( "P(x > 72) = 1 - P( z ≤ (72-70)/6.4) = 1 - P(z≤ .3125) = 1 - .6227 = .3773 \r
\n" ); document.write( "\n" ); document.write( "μ = 70 , σ = 6.4
\n" ); document.write( "Find the proportion of male college students whose height is greater than 72 inches.
\n" ); document.write( "SAMPLE: 10 heights
\n" ); document.write( "P( x > 72) = 1 - P(\"z+%3C=+%2872-70%29%2F%286.4%2Fsqrt%2810%29%29\"= 1 -P(z=.9882) = 1-.8385 = .1615
\n" ); document.write( "TI normalcdf(z) gives the portion of the area under the standard normal curve to the LEFT of the z-value entered.
\n" ); document.write( "Important to Understand z -values as they relate to the Standard Normal curve:
\n" ); document.write( "Below: z = 0, z = ± 1, z= ±2 , z= ±3 are plotted.
\n" ); document.write( "For ex: normalcdf(2) - normalcdf(-2) would give the portion of the area under the curve between those two z-values
\n" ); document.write( "Note: z = 0 , 50% of the area under the curve is to the left and 50% to the right
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