document.write( "Question 675624: Suppose certain coins have weights that are normally distributed with a mean of 5.338 g and a standard deviation of 0.068 g. A vending machine is configured to accept those coins with weights between 5.208 g and 5.468 g.\r
\n" ); document.write( "\n" ); document.write( "a. If 250 different coins are inserted into the vending machine, what is the expected number of rejected coins?\r
\n" ); document.write( "\n" ); document.write( "The expected number of rejected coins is____(Round to the nearest integer)
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\n" ); document.write( "\n" ); document.write( "If you could tell me how to do it rather than just give the answer that be helpful considering that kind of the point. Since i been following the example and i keep getting the wrong answer(online homework, infinite # of tries at the cost of 0.5 reduced per retry).\r
\n" ); document.write( "\n" ); document.write( "Its kinda frustrating, since i been following the damn example and even other methods that i found googling. Also if you can explain it by using the TI-83 calculator that would be even better.\r
\n" ); document.write( "\n" ); document.write( "What i been doing is (x-median)/Standard devuation, so:
\n" ); document.write( " (5.208-5.338)/0.068 and (5.468 -5.338)/0.068
\n" ); document.write( "to get the Z score. After that i find the area to the right and left.
\n" ); document.write( "Since i don't remember the formula or i don't know it. I google to look for it and i think its this one.
\n" ); document.write( "http://homepage.smc.edu/mcgraw_colleen/math_52/Finding%20%20p-values.pdf
\n" ); document.write( "So i do this after.
\n" ); document.write( "Calculator TI-83
\n" ); document.write( "normalcdf(-10,result of (5.208-5.338)/0.068,) and normalcdf(result of(5.468 -5.338)/0.068,10)
\n" ); document.write( "After that i sum their answers and finally i multiply it by 250. I haved tried but it says its wrong(only 3 tries till the right answer)\r
\n" ); document.write( "\n" ); document.write( "Ty for your help. \n" ); document.write( "
Algebra.Com's Answer #419977 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
 
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document.write( "Hi
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document.write( "μ = 5.338  ,  σ = .068 
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document.write( "vending machine is configured to accept those coins with weights between 5.208 g and 5.468 g.
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document.write( "SAMPLE: 250 different coins
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document.write( "P(5.208 < x < 5.468) = P(\"z+%3C=+%285.468-5.338%29%2F%28.068%2Fsqrt%28250%29%29\"  -   P(\"z+%3C=+%285.208-5.338%29%2F%28.068%2Fsqrt%28250%29%29\"
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document.write( "find this difference and multiply times 250 (rounding UP to the nearest integer )
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document.write( "TI normalcdf(z)  gives the portion of the area under the standard normal curve to the LEFT of the z-value entered.
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document.write( "Actually can do in one step for between two z-values: normalcdf(smaller z, larger z)
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document.write( "Important to Understand z -values as they relate to the Standard Normal curve:
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document.write( "Below:  z = 0, z = ± 1, z= ±2 , z= ±3 are plotted.  
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document.write( "For ex: normalcdf(2) - normalcdf(-2) would give the portion of the area under the curve between those two z-values 
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document.write( "Note: z = 0 , 50% of the area under the curve is to the left and 50%  to the right
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