document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=675639>Question 675639</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Tan (1/2 theta)=sqrt 3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #419969 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=419969\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Tan (1/2 theta)=sqrt 3<BR>\n" );
document.write( "----<BR>\n" );
document.write( "Take the tan^-1 of both sides to get:<BR>\n" );
document.write( "(theta)/2 = tan^-1(sqrt(3))<BR>\n" );
document.write( "----<BR>\n" );
document.write( "(theta)/2 = pi/6<BR>\n" );
document.write( "---<BR>\n" );
document.write( "theta = pi/3 or 60 degrees<BR>\n" );
document.write( "=======================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "============== </SPAN>\n" );
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