document.write( "Question 675625: Can u show me working for
\n" ); document.write( "X/3 + 2 = 9
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Algebra.Com's Answer #419947 by rm29924(97)\"\" \"About 
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x/3 + 2 = 9
\n" ); document.write( "we want to get x by itself
\n" ); document.write( "so we subtract 2 from both sides
\n" ); document.write( "x/3 + 2 = 9
\n" ); document.write( " - 2 -2\r
\n" ); document.write( "\n" ); document.write( "x/3=7
\n" ); document.write( "to get rid of the 3 on the bottom we multipy both sides by 3
\n" ); document.write( "3(x/3) = 7(3)
\n" ); document.write( "3 is the same as 3/1
\n" ); document.write( "3/1(x/3) 3x/3 and 3 cancels out
\n" ); document.write( "x = 21\r
\n" ); document.write( "\n" ); document.write( "plug in the answer to check your work
\n" ); document.write( "x/3 + 2 = 9
\n" ); document.write( "21/3 + 2 = 9
\n" ); document.write( "21 divied by 3 = 7
\n" ); document.write( "7+2=9
\n" ); document.write( "9=9
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