document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=675590>Question 675590</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Anne and Nancy use a metal alloy that is 17.3% copper to make jewelry. How many ounces of a 17% alloy must be mixed with a 18% alloy to form 80 ounces of the desired alloy? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #419937 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=419937\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Anne and Nancy use a metal alloy that is 17.3% copper to make jewelry. How many ounces of a 17% alloy must be mixed with a 18% alloy to form 80 ounces of the desired alloy?<BR>\n" );
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document.write( "let x=amt of 17% alloy to be mixed<BR>\n" );
document.write( "80-x=amt of 18% alloy to be mixed<BR>\n" );
document.write( "..<BR>\n" );
document.write( "17%x+18%(80-x)=17.3%*80<BR>\n" );
document.write( ".17x+14.4-.18x=13.84<BR>\n" );
document.write( ".01x=.56<BR>\n" );
document.write( "x=56<BR>\n" );
document.write( "80-x=24<BR>\n" );
document.write( "amt of 17% alloy to be mixed=56 oz<BR>\n" );
document.write( "amt of 18% alloy to be mixed=24 oz </SPAN>\n" );
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