document.write( "Question 61075This question is from textbook Algebra 2 with trigonometry
\n" );
document.write( ": A total of $1150 was investe3d , part of it at 12% and part at 11%. The total yield was $133.75. How much was invested at each rate? \n" );
document.write( "
Algebra.Com's Answer #41991 by joyofmath(189)![]() ![]() ![]() You can put this solution on YOUR website! A total of $1150 was invested, part of it at 12% and part at 11%. The total yield was $133.75. How much was invested at each rate?\r \n" ); document.write( "\n" ); document.write( "Let A = amount invested at 12%. \n" ); document.write( "Let B = amount invested at 11%.\r \n" ); document.write( "\n" ); document.write( "A total of $1150 was invested so \n" ); document.write( "The total yield = \n" ); document.write( "Since \n" ); document.write( "Substitute \n" ); document.write( "and you get \n" ); document.write( "Simplify and you get \n" ); document.write( "Simplify more and you get \n" ); document.write( "Subtract 126.5 from both sides and you get \n" ); document.write( "So, $725 was invested at 12% A total of $1150 was invested so the balance, $425, was invested at 11%.\r \n" ); document.write( "\n" ); document.write( "To verify, plug the values of A and B into \n" ); document.write( " |